**Solution**

Realizing that there is no way we can use a normal “U sub” method we learned from highschool, we need to be a bit creative and find a way to tackle this integral by playing around with the polynomial in the denominator.

First divide top and bottom by ,

Since,

We need to somehow make the derivative of the denominator “appears” in the numerator by completing the square in the denominator and add 1 and subtract 1 in both integrals.

Let , we have

Then the rest is routine and easy!

Sub back the *x*,

We can drop the absolute value sign since and

Therefore,

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